Introduction to calculus

Introduction to calculus:

Here the function f(x) = (x + 5) have the following conditions,
(x + 2)
At point zero, we can say that numerator = 0
So, x+5 = 0 => x=-5.
At vertical asymptote at x=-2, since denominator = 0
x+2 = 0 => x=-2
At y-intercept, the function of x equal zero, then
f(x) = 0, (0 + 5) = 5